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5 в моем хитром расчете время, потр. в первом цикле (1такт) + время между циклами (3такта) + время во втором цикле (1такт):
r8 = r8 xor r8, f4 = dm(i1,m6), f2 = pm(i12,m14);
lcntr = IIRORD-1, do (pc,1) until lce;
f8 = f2*f4, f12 = f8+f12, f4 = dm(i1,m6), f2 = pm(i12,m14);
f8 = f2*f4, f12 = f8+f12;
f6 = f8+f12, r8 = m5;
r12 = r12 xor r12, f4 = dm(i1,m6), f2 = pm(i12,m14);
lcntr = IIRORD-1, do (pc,1) until lce;
f8 = f2*f4, f12 = f8+f12, f4 = dm(i1,m6), f2 = pm(i12,m14);
f8 = f2*f4, f12 = f8+f12, f2 = pm(i12,m14);
f8 = f2*f6, f12 = f8+f12;
f12 = f8+f12, dm(i1,m6) = f6;
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